Which of the following has been arranged in o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the order,calculate the oxidation number $(ON)$ of nitrogen in each species:$NH_4^+$: $x + 4(+1) = +1 \implies x = -3$$N_2H_4$: $2x +

Vedclass · Accepted Answer

$NH_4^+ < N_2H_4 < NH_2OH < N_2O$

Vedclass · Answer

(C) To determine the order,calculate the oxidation number $(ON)$ of nitrogen in each species:$NH_4^+$: $x + 4(+1) = +1 \implies x = -3$$N_2H_4$: $2x + 4(+1) = 0 \implies 2x = -4 \implies x = -2$$NH_2OH$: $x + 2(+1) + (-2) + (+1) = 0 \implies x + 1 = 0 \implies x = -1$$N_2O$: $2x + (-2) = 0 \implies 2x = +2 \implies x = +1$Thus,the increasing order is: $\mathop {NH_4^+}\limits_{(-3)} < \mathop {N_2H_4}\limits_{(-2)} < \mathop {NH_2OH}\limits_{(-1)} < \mathop {N_2O}\limits_{(+1)}$.

Which of the following has been arranged in order of increasing oxidation number of nitrogen?

Similar Questions

In which of the following acids is the phosphorus atom present in its lowest oxidation state?

The oxidation state of sulfur in the anions $SO_3^{2-}$,$S_2O_4^{2-}$,and $S_2O_6^{2-}$ increases in the order:

What are the respective oxidation states of sulphur atoms numbered $1$ to $4$ in the tetrathionate ion $(S_4O_6^{2-})$ shown below?

What is the oxidation number of sulfur in $Na_2S_4O_6$?

Calculate the oxidation number of $C$ in glucose $(C_{6}H_{12}O_{6})$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module